子类是否可以直接访问父类的私有成员?
private
成员 => 子类不能直接访问父类的私有成员示例:继承中的访问级别
Dmeo
#include <iostream>
#include <string>
using namespace std;
class Parent
{
private:
int mv;
public:
Parent()
{
mv = 100;
}
int value()
{
return mv;
}
};
class Child : public Parent
{
public:
int addValue(int v)
{
mv = mv + v; // ???? 如何访问父类的非公有成员
}
};
int main()
{
return 0;
}
编译
test.cpp: In member function ‘int Child::addValue(int)’:
test.cpp:8:13: error: ‘int Parent::mv’ is private
int mv;
^
test.cpp:23:13: error: within this context
mv = mv + v;
面对对象中的访问级别不只是 public
和 private
可以定义 protected
访问级别
关键字 protected
的意义
示例:protected
使用
Demo
#include <iostream>
using namespace std;
class Parent
{
protected:
int mv;
public:
Parent()
{
mv = 100;
}
int value()
{
return mv;
}
};
class Child : public Parent
{
public:
int addValue(int v)
{
mv = mv + v;
}
};
int main()
{
Parent p;
cout << "p.mv = " << p.value() << endl;
p.mv = 1000; // error:外界无法访问
Child c;
cout << "c.mv = " << c.value() << endl;
c.addValue(50);
cout << "c.mv = " << c.value() << endl;
c.mv = 10000; // error:外界无法访问
return 0;
}
编译运行
test.cpp: In function ‘int main()’:
test.cpp:8:13: error: ‘int Parent::mv’ is protected
int mv;
^
test.cpp:33:7: error: within this context
p.mv = 1000;
^
test.cpp:8:13: error: ‘int Parent::mv’ is protected
int mv;
^
test.cpp:41:7: error: within this context
c.mv = 1000;
^
问题:为什么面对对象中需要 protected
?
protected
关键字是为了继承而专门设计的protected
就无法完成真正意义上的代码复用示例:组合和继承的综合实例
Dmeo
#include <iostream>
#include <string>
#include <sstream>
using namespace std;
class Object
{
protected:
string mName;
string mInfo;
public:
Object()
{
mName = "Object";
mInfo = "";
}
string name()
{
return mName;
}
string info()
{
return mInfo;
}
};
class Point : public Object
{
private:
int mX;
int mY;
public:
Point(int x = 0, int y = 0)
{
ostringstream s;
mX = x;
mY = y;
mName = "Point";
s << "P(" << mX << ", " << mY << ")";
mInfo = s.str();
}
int x()
{
return mX;
}
int y()
{
return mY;
}
};
class Line : public Object
{
private:
Point mP1;
Point mP2;
public:
Line(Point p1, Point p2)
{
ostringstream s;
mP1 = p1;
mP2 = p2;
mName = "Line";
s << "Line from " << mP1.info() << " to " << mP2.info();
mInfo = s.str();
}
Point begin()
{
return mP1;
}
Point end()
{
return mP2;
}
};
int main()
{
Object o;
Point p(1, 2);
Point pn(5, 6);
Line l(p, pn);
cout << o.name() << endl;
cout << o.info() << endl;
cout << endl;
cout << p.name() << endl;
cout << p.info() << endl;
cout << endl;
cout << l.name() << endl;
cout << l.info() << endl;
return 0;
}
编译运行
原文:https://www.cnblogs.com/bky-hbq/p/13903892.html