快速统计出字母出现的次数

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <time.h>


int main() {

    char chs[] = "absdfdsfsafsafssdc";
    char arr[26] = {0};

    int len = strlen(chs);
    for (int i = 0; i < len; ++i) {
        arr[chs[i] - ‘a‘]++;
    }
    for (int j = 0; j < 29; ++j) {
        if(arr[j] ){
            printf("%c 出现次数：%d\n", j + ‘a‘, arr[j]);
        }

    }

    return 0;
}