求1000-2000之间的闰年，C语言代码实现

    int main()
    {
    int count = 0;//解法一
    int year = 1000;
    for (year = 1000; year <= 2000; year++)
    {
        if ((year % 4 == 0 && year % 100 != 0) || (year % 400 == 0))
        {
            printf("%d ", year);
            count++;
        }
    }
    printf("\n总共有%d年\n", count);
    return 0;
}

运行结果
![](https://s4.51cto.com/images/blog/202010/31/b3a78d508b26d188920225df9ccdf342.png?x-oss-process=image/watermark,size_16,text_QDUxQ1RP5Y2a5a6i,color_FFFFFF,t_100,g_se,x_10,y_10,shadow_90,type_ZmFuZ3poZW5naGVpdGk=)

求1000-2000之间的闰年，C语言代码实现

原文：https://blog.51cto.com/14950896/2545765