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js合并字符串的3种方法和效率

时间:2020-11-15 00:20:56      阅读:53      评论:0      收藏:0      [点我收藏+]

/* abc abc abc*/

function concat(s,n)
{
let a = new Array(n);
a.fill(s);
let str = a.join(‘‘);
a = null;
return str;
}

function concat1(s, n){
let count = n;
let str = ‘‘;
while(count > 0)
{
str += s;
count --;
}
return str;
}
function tco(f) {
var value;
var active = false;
var accumulated = [];
return function accumulator() {
accumulated.push(arguments);
if(!active) {
active = true;
while(accumulated.length) {
value = f.apply(this, accumulated.shift());
}
active = false;
return value;
}
};
}
const concat2 = tco(function ( s,n)
{
if(n == 1) return s;
return concat2(s, n-1);
})
let n = 10000*100;
let startTime = new Date();
let str = concat(‘abc‘,n);
let endTime = new Date();

let str1 = concat1(‘abc‘,n);
let endTime1 = new Date();
let str2 = concat2(‘abc‘,n);
//console.log(‘the result is \"‘ + str2 + ‘\"‘);
let endTime2 = new Date();
//console.log(‘the result is \"‘ + str + ‘\"‘);
console.log(‘time:‘ + (endTime.getTime() - startTime.getTime()));
console.log(‘time1:‘ + (endTime1.getTime() - endTime.getTime()));
console.log(‘time2:‘ + (endTime2.getTime() - endTime1.getTime()));

1. 10000*100

time:135
time1:356
time2:171

2:10000*1000

time:1348
time1:5204
time2:1132

 

js合并字符串的3种方法和效率

原文:https://www.cnblogs.com/yanjianjiang/p/13975281.html

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