UVa 621 Secret Research

At a certain laboratory results of secret research are thoroughly encrypted. A result of a single experiment is stored as an information of its completion:

`positive result‘, `negative result‘, `experiment failed‘ or `experiment not completed‘

The encrypted result constitutes a string of digits S, which may take one of the following forms:

positive result 		 S = 1 or S = 4 or S = 78 

negative result 		 S = S35 

experiment failed 		 S = 9S4 

experiment not completed 		 S = 190S

(A sample result S35 means that if we add digits 35 from the right hand side to a digit sequence then we shall get the digit sequence corresponding to a failed experiment)

You are to write a program which decrypts given sequences of digits.

Input 

A integer n stating the number of encrypted results and then consecutive n lines, each containing a sequence of digits given as ASCII strings.

Output 

For each analysed sequence of digits the following lines should be sent to output (in separate lines):

		 + 		  for a positive result
		 - 		  for a negative result
		 * 		  for a failed experiment
		 ? 		  for a not completed experiment

In case the analysed string does not determine the experiment result, a first match from the above list should be outputted.

Sample Input 

4
78
7835
19078
944

Sample Output 

+
-
?
*

给一个由数字组成的字符串，判断它是题目中描述的哪中格式的，输出相应的符号即可，特别简单几分钟切掉

 1 #include<iostream>
 2 #include<cstdio>
 3 #include<cstring>
 4 
 5 using namespace std;
 6 
 7 int main()
 8 {
 9     int n;
10     char s[10000];
11 
12     scanf("%d",&n);
13     getchar();
14 
15     while(n--)
16     {
17         gets(s);
18         int len=strlen(s);
19         if( ( len==1 && (s[0]==‘1‘||s[0]==‘4‘) ) || ( len==2 && s[0]==‘7‘ &&s[1]==‘8‘ ) )
20             printf("+\n");
21         else if( len>=3 && s[len-1]==‘5‘ && s[len-2]==‘3‘ )
22             printf("-\n");
23         else if( len>=3 && s[0]==‘9‘ && s[len-1]==‘4‘ )
24             printf("*\n");
25         else if( len>=4 && s[0]==‘1‘ && s[1]==‘9‘ && s[2]==‘0‘ )
26             printf("?\n");
27     }
28 
29     return 0;
30 }

[C++]

UVa 621 Secret Research

原文：http://www.cnblogs.com/lzj-0218/p/3518629.html