import pickle
import os
class User:
def init(self,name,id,tel,card):
self.name = name
self.id = id
self.tel = tel
self.card = card
@staticmethod
def xieru(x):
path =os.path.join(os.getcwd(),‘a.db‘)
f = open(path,‘wb‘)
pickle.dump(x,f)
f.close()
@staticmethod
def duqu():
path = os.path.join(os.getcwd(),‘a.db‘)
f = open(path,‘rb‘)
a = pickle.load(f)
f.close()
return a
class Admin:
def init(self,name,passwd):
self.name = name
self.passwd = passwd
def login(self):
for i in range(3):
name = input(‘输入管理员账号：‘)
passwd = input(‘输入管理员密码：‘)
if name == self.name and passwd == self.passwd :
print(‘登陆成功！‘)
return True
else:
print(‘登录失败！‘)
class Card:
def init(self,num,money,pwd):
self.num = num
self.money = money
self.pwd = pwd
self.clock = False
from user import User
from card import Card
from admin import Admin
import random
class Atm:
def init(self):
self.user_dict = {}
def welcome(self):
print(‘*‘ * 30)
print(‘*‘ + " " * 6 + ‘开户（1）‘ + ‘ ‘ + ‘查询(2)‘ + ‘ ‘ * 6 + ‘*‘)
print("*" + " " * 6 + ‘取款（3）‘ + ‘ ‘ + ‘存款(4)‘ + ‘ ‘ * 6 + ‘*‘)
print("*" + " " * 6 + ‘转账（5）‘ + ‘ ‘ + ‘改密(6)‘ + ‘ ‘ * 6 + ‘*‘)
print("*" + " " * 6 + ‘锁定（7）‘ + ‘ ‘ + ‘解锁(8)‘ + ‘ ‘ * 6 + ‘*‘)
print("*" + " " * 6 + ‘销户（9）‘ + ‘ ‘ + ‘退出(0)‘ + ‘ ‘ * 6 + ‘*‘)
print(‘*‘ * 30)
def mkcard(self):
cardid = ‘‘
for i in range(6):
a = str(random.randint(0,9))
cardid += a
return cardid
if name == ‘main‘:
atm = Atm()
admin = Admin(‘admin‘,‘123456‘)
if admin.login():
try:
atm.user_dict = User.duqu()
except Exception as e:
print(‘ ‘)
while True:
atm.welcome()
print(atm.user_dict)
choice = int(input(‘请输入想要执行的操作：‘))
if choice == 1:
name = input(‘输入姓名：‘)
cid = input(‘身份证号：‘)
tel = input(‘手机号：‘)
pwd1 = input(‘输入密码：‘)
pwd2 = input(‘再次确认密码：‘)
if pwd1 == pwd2 :
num = atm.mkcard()
money = int(input(‘请输入开户金额（>=10$）：‘))
if money < 10 :
print(‘金额太少，开户失败‘)
continue
card = Card(num,money,pwd2)
user = User(name,cid,tel,card)
atm.user_dict[num] = user
# User.xieru(fdy.user_dict)
print(‘开户成功，您的卡号为：%s 卡上余额%.2f：‘%(num,money))
else:
print(‘密码不一致，开户失败‘)
elif choice == 2:
num = input(‘请输入卡号：‘)
if num in atm.user_dict:
user = atm.user_dict.get(num)
if user.card.clock == False:
for i in range(3):
pwd = input(‘请输入密码：‘)
if pwd == user.card.pwd:
print(‘卡号：%s 姓名：%s 手机号：%s 余额：%.2f￥‘%
(num,user.name,user.tel,user.card.money))
break
else:
print(‘密码错误！‘)
else:
print(‘密码错误三次，卡已被锁！‘)
user.card.clock = True
# ‘‘‘此处切记要将字典信息再保存一遍‘‘‘
# User.xieru(fdy.user_dict)
else:
print(‘此卡已锁，请先解锁！‘)
else:
print(‘卡号不存在！‘)
elif choice == 3:
num = input(‘请输入卡号：‘)
if num in atm.user_dict:
user = atm.user_dict.get(num)
if user.card.clock == False:
for i in range(3):
pwd = input(‘请输入密码：‘)
if pwd == user.card.pwd:
qumoney = int(input(‘请输入取款金额：‘))
if qumoney <= user.card.money:
user.card.money-=qumoney
# User.xieru(fdy.user_dict)
print(‘取款成功!卡上余额：%.2f￥‘%(user.card.money))
break
else:
print(‘余额不足！‘)
break
else:
print(‘密码错误！‘)
else:
print(‘密码错误三次，卡已被锁！‘)
user.card.clock = True
# User.xieru(fdy.user_dict)
else:
print(‘此卡已锁，请先解锁！‘)
else:
print(‘卡号不存在！‘)
elif choice == 4:
num = input(‘请输入卡号：‘)
if num in atm.user_dict:
user = atm.user_dict.get(num)
if user.card.clock == False:
for i in range(3):
pwd = input(‘请输入密码：‘)
if pwd == user.card.pwd:
qumoney = float(input(‘请输入存款金额：‘))
user.card.money += qumoney
# User.xieru(fdy.user_dict)
print(‘存款成功！卡上余额：%.2f￥‘%(user.card.money))
break
else:
print(‘密码错误！‘)
else:
print(‘密码错误三次，卡已被锁！‘)
user.card.clock = True
# User.xieru(fdy.user_dict)
else:
print(‘此卡已锁，请先解锁！‘)
else:
print(‘卡号不存在！‘)
elif choice == 5:
num = input(‘请输入卡号：‘)
if num in atm.user_dict:
user = atm.user_dict.get(num)
if user.card.clock == False:
for i in range(3):
pwd = input(‘请输入密码：‘)
if pwd == user.card.pwd:
qumoney = float(input(‘请输入转账金额：‘))
num1 = input(‘请输入对方卡号：‘)
if num1 in atm.user_dict:
user1 = atm.user_dict.get(num1)
if qumoney <= user.card.money:
print(‘y:确认转账 n:取消转账‘)
answer = input(‘‘)
if answer == ‘y‘:
user.card.money-=qumoney
user1.card.money+=qumoney
# User.xieru(fdy.user_dict)
print(‘转账成功！卡上余额：%.2f￥‘%(user.card.money))
break
elif answer == ‘n‘:
print(‘已取消转账！‘)
break
else:
print(‘金额不足！‘)
break
else:
print(‘对方卡号不存在！‘)
break
else:
print(‘密码错误！‘)
else:
print(‘密码错误三次，卡已被锁！‘)
user.card.clock = True
# User.xieru(fdy.user_dict)
else:
print(‘此卡已锁，请先解锁！‘)
else:
print(‘卡号不存在！‘)
elif choice == 6:
num = input(‘请输入卡号：‘)
if num in atm.user_dict:
user = atm.user_dict.get(num)
if user.card.clock == False:
for i in range(3):
pwd = input(‘请输入密码：‘)
if pwd == user.card.pwd:
pwd1 = input(‘请输入新的密码：‘)
pwd2 = input(‘请再次输入新的密码：‘)
if pwd1 == pwd2 :
user.card.pwd = pwd2
# User.xieru(fdy.user_dict)
print(‘密码修改成功！‘)
break
else:
print(‘密码错误！‘)
else:
print(‘密码错误三次，卡已被锁！‘)
user.card.clock = True
# User.xieru(fdy.user_dict)
else:
print(‘此卡已锁，请先解锁！‘)
else:
print(‘卡号不存在！‘)
elif choice == 7:
num = input(‘请输入卡号：‘)
if num in atm.user_dict:
user = atm.user_dict.get(num)
pwd = input(‘请输入密码：‘)
if pwd == user.card.pwd:
user.card.clock = True
# User.xieru(fdy.user_dict)
print(‘卡已锁！‘)
else:
print(‘密码错误！‘)
else:
print(‘卡号无效！‘)
elif choice == 8:
num = input(‘请输入卡号：‘)
if num in atm.user_dict:
user = atm.user_dict.get(num)
pwd = input(‘请输入密码：‘)
if pwd == user.card.pwd:
user.card.clock = False
# User.xieru(fdy.user_dict)
print(‘卡已解锁！‘)
else:
print(‘密码错误！‘)
else:
print(‘卡号无效！‘)
elif choice == 9:
num = input(‘请输入卡号：‘)
if num in atm.user_dict:
user = atm.user_dict.get(num)
if user.card.clock == False:
for i in range(3):
pwd = input(‘请输入密码：‘)
if pwd == user.card.pwd:
print(‘确定要销户吗？‘)
answer = input(‘y/n:‘)
if answer == ‘y‘:
atm.user_dict.pop(num)
print(‘销户成功！‘)
User.xieru(atm.user_dict)
break
else:
print(‘已取消操作！‘)
break
else:
print(‘密码错误！‘)
else:
print(‘密码错误三次，卡已被锁！‘)
user.card.clock = True
# User.xieru(fdy.user_dict)
else:
print(‘此卡已锁，请先解锁！‘)
else:
print(‘卡号不存在！‘)
elif choice == 0:
#程序正常退出保存数据（非正常退出则无法保存）
User.xieru(atm.user_dict)
break
开户
查询
取款
存款
改密
销户
psp2.1 任务内容 计划完成需要的时间（min） 实际完成需要的时间（min）
Planning 计划 10 9
Estimate 估计这个任务需要多少时间，并规划大致工作步骤 10 7
Development 开发 140 120
Analysis 需求分析 12 5
Design Spec 生成设计文档 5 5
Design Review 设计复审 5 5
Coding Standard 代码规范 3 2
Design 具体设计 10 12
Coding 具体编码 36 21
Code Review 代码复审 5 7
Test 测试 10 15
Reporting 报告 9 6
Test Report 测试报告 3 2
Size Measurement 计算工作量 2 1
Postmortem & Process Improvement Plan 事后总结 3 3
原文：https://www.cnblogs.com/baifei/p/13998412.html