这个板子是网上搜到的,稍微改了改,里面用到了逆元,不是是很熟,将来有机会一定弄明白 ??
#include <cstdio>
const int N = 1e5 + 5;
const int mod = 1e9 + 7;
typedef long long ll;
ll f[N];
ll qpow(ll a, ll b) {
ll ans = 1, base = a;
while (b) {
if (b & 1) ans = ans * base % mod;
base = base * base % mod;
b >>= 1;
}
return ans;
}
void init() {
f[0] = 1;
for (int i = 1; i <= 2e5; i++) {
f[i] = f[i - 1] * i % mod;
}
}
ll cal(ll n, ll m) {
if (n < m) return 0;
return 1ll * f[n] * qpow(f[m], mod - 2) % mod * qpow(f[n - m], mod - 2) % mod;
}
原文:https://www.cnblogs.com/chantmee/p/14167344.html