简单DP,矩阵链乘思路
#include <iostream>
#include <algorithm>
#include <cstdio>
#include <cstring>
using namespace std;
const int maxn= 105;
const int INF= 0x3f3f3f3f;
int cs[maxn];
int dp[maxn][maxn];
int main(int argc, char const *argv[])
{
int n;
scanf("%d", &n);
memset(dp, 0x3f, sizeof(dp));
for (int i= 0; i< n; ++i){
scanf("%d", cs+i);
}
int ui= n-1;
for (int i= 0; i< ui; ++i){
dp[i][i+1]= 0;
}
for (int d= 2; d< n; ++d){
ui= n-d;
for (int i= 0; i< ui; ++i){
int j= i+d;
int &s= dp[i][j];
for (int k= i+1; k< j; ++k){
s= min(s, cs[k]*cs[i]*cs[j]+dp[i][k]+dp[k][j]);
}
}
}
cout<<dp[0][n-1];
return 0;
}
原文:https://www.cnblogs.com/Idi0t-N3/p/14178158.html