首页 > 编程语言 > 详细

线程竞争

时间:2020-12-26 18:02:38      阅读:23      评论:0      收藏:0      [点我收藏+]

code
from threading import Thread
import os,time
 
n=100
 
def work():
    global n
    temp=n
    time.sleep(0.1)
    n=temp-1
 
l=[]
for i in range(100):
    p=Thread(target=work)
    l.append(p)
    p.start()
 
for p in l:
    p.join()
 
 
print(n)    #结果可能为99
outputs
macname@MacdeMacBook-Pro py % python3 cccccc.py
99
macname@MacdeMacBook-Pro py % 

 

由于所有线程初始值都是100,所以最后结果为99
加入线程锁后
 
from threading import Thread, Lock
import os, time
 
 
n = 100
def work():
    global n
    lock.acquire()
    temp = n
    time.sleep(0.1)
    n = temp - 1
    lock.release()
 
 
 
 
if __name__ == __main__:
    lock = Lock()
    l = []
    for i in range(100):
        p = Thread(target=work)
        l.append(p)
        p.start()
    for p in l:
        p.join()
 
 
    print(n)  #0
outputs
macname@MacdeMacBook-Pro py % python3 cccccc.py
0
macname@MacdeMacBook-Pro py % 

 

 
 
 
 
 
 
 
 
 
 
 
 

线程竞争

原文:https://www.cnblogs.com/sea-stream/p/14192549.html

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!