【剑指】从尾到头打印链表

# Definition for singly-linked list.
# class ListNode:
#     def __init__(self, x):
#         self.val = x
#         self.next = None

class Solution:
    def reversePrint(self, head: ListNode) -> List[int]:
        p = head
        ans = []
        while p:
            ans.append(p.val)
            p = p.next
        return ans[::-1]

【剑指】从尾到头打印链表

原文：https://www.cnblogs.com/wangshujaun/p/14220494.html