有如下值集合 [11,22,33,44,55,66,77,88,99,90...],将所有大于 66 的值保存至字典的第一个key中,将小于 66 的值保存至第二个key的值中。
即: {‘k1‘: 大于66的所有值, ‘k2‘: 小于66的所有值}
li = [11, 22, 33, 44, 55, 66, 77, 88, 99, 90]
a = {"k1":[], "k2":[]}
for i in li:
if i > 66:
a["k1"].append(i)
elif i == 66:
pass
elif i < 66:
a["k2"].append(i)
print(a)=======>{‘k1‘: [77, 88, 99, 90], ‘k2‘: [11, 22, 33, 44, 55]}
for i in li:
b = i.strip()
if (b.startswith("a") or b.startswith("A")) and b.endswith("c"):
print(b)
for i1 in tu:
b1 = i1.strip()
if (b1.startswith("a") or b1.startswith("A")) and b1.endswith("c"):
print(b1)
for i2 in dic.values():
b3 = i2.strip()
if (b3.startswith("a") or b3.startswith("A")) and b3.endswith("c"):
print(b3)
li = ["手机", "电脑", ‘鼠标垫‘, ‘游艇‘]
for k, v in enumerate(li, 1):===>先排序
print(k, v)
inp = int(input("请输入序号:"))====>然后输入号码
print(li[inp - 1])
功能要求:
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goods = [ { "name" : "电脑" , "price" : 1999 }, { "name" : "鼠标" , "price" : 10 }, { "name" : "游艇" , "price" : 20 }, { "name" : "美女" , "price" : 998 }, ] |
原文:https://www.cnblogs.com/wode110/p/14290854.html