/** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode() : val(0), next(nullptr) {} * ListNode(int x) : val(x), next(nullptr) {} * ListNode(int x, ListNode *next) : val(x), next(next) {} * }; */ class Solution { public: ListNode* mergeTwoLists(ListNode* l1, ListNode* l2) { if (l1 == nullptr) { return l2; } else if (l2 == nullptr) { return l1; } else if (l1->val < l2->val) { l1->next = mergeTwoLists(l1->next, l2); return l1; } else { l2->next = mergeTwoLists(l1, l2->next); return l2; } } };
如果节点的值小,我们就去比这个小节点的下一个指向和原来一起比较的节点
递归
原文:https://www.cnblogs.com/ranzhong/p/14315969.html