let arr1 =[1,2,3] //跟 let arr2 =[4,6,5] //子 let arr3 =[1,2,6] //根子都有 let frist =arr3.filter(item=> arr1.indexOf(item)>-1) //跟 let frist1 =arr3.filter(item=> arr2.indexOf(item)>-1)//子 console.log(frist) console.log(frist1)
原文：https://www.cnblogs.com/wangkunlong/p/14345642.html