用递归计算1-100所有自然数的和

package com.atguigu.exer;

public class RecursionTest {

    public static void main(String[] args){
        Recursion recur = new Recursion();
        System.out.println(recur.getSum(100));
    }
}

class Recursion{
    public int getSum(int n){
        if(n == 1){
            return 1;
        }else{
            return n + getSum(n - 1);
        }
    }
    
}