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岛屿数量

时间:2021-02-24 23:38:22      阅读:26      评论:0      收藏:0      [点我收藏+]

给你一个由 ‘1‘(陆地)和 ‘0‘(水)组成的的二维网格,请你计算网格中岛屿的数量。

岛屿总是被水包围,并且每座岛屿只能由水平方向和/或竖直方向上相邻的陆地连接形成。

此外,你可以假设该网格的四条边均被水包围。

 

示例 1:

输入:grid = [
["1","1","1","1","0"],
["1","1","0","1","0"],
["1","1","0","0","0"],
["0","0","0","0","0"]
]
输出:1

 

 

1、dfs

#include <vector>
#include <iostream>
#include <queue>

using namespace std;

class Solution {
public:
    int numIslands(vector<vector<char>> &grid) {
        int N = grid.size();
        int M = grid[0].size();
        vector<vector<bool>> visited(N, vector<bool>(M, false));
        int res = 0;
        queue<pair<int, int>> qe;
        for (int i = 0; i < N; ++i) {
            for (int j = 0; j < M; ++j) {
                if (!visited[i][j] && grid[i][j] != 0) {
                    qe.push({i, j});
                    res++;
                }
                while (!qe.empty()) {
                    auto ele = qe.front();
                    qe.pop();
                    if ((ele.first + 1) < N && !visited[ele.first + 1][ele.second] &&
                        grid[ele.first + 1][ele.second] != 0) {
                        qe.push({ele.first + 1, ele.second});
                        visited[ele.first + 1][ele.second] = true;
                    }
                    if ((ele.second + 1) < M && !visited[ele.first][ele.second + 1] &&
                        grid[ele.first][ele.second + 1] != 0) {
                        qe.push({ele.first, ele.second + 1});
                        visited[ele.first][ele.second + 1] = true;
                    }
                    if ((ele.first - 1) > -1 && !visited[ele.first - 1][ele.second] &&
                        grid[ele.first - 1][ele.second] != 0) {
                        qe.push({ele.first - 1, ele.second});
                        visited[ele.first - 1][ele.second] = true;
                    }
                    if ((ele.second - 1) > -1 && !visited[ele.first][ele.second - 1] &&
                        grid[ele.first][ele.second - 1] != 0) {
                        qe.push({ele.first, ele.second - 1});
                        visited[ele.first][ele.second - 1] = true;
                    }
                }
            }
        }
        return res;
    }
};

int main() {
    vector<vector<char>> grid{{1, 1, 1},
                              {0, 1, 0},
                              {1, 1, 1}};
    Solution s;
    cout << s.numIslands(grid) << endl;
}

 

岛屿数量

原文:https://www.cnblogs.com/zhangzhangtabszj/p/14443728.html

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