首页 > 编程语言 > 详细

java之map作为参数和结果类型

时间:2021-03-03 15:02:46      阅读:106      评论:0      收藏:0      [点我收藏+]
xml:
<select id="getData" resultType="map" parameterType="map">
    select * from student where 1 = 1
    <if test="name != null and name != ‘‘">
        and name like concat(‘%‘, #{name}, ‘%‘)
    </if>
    <if test="address != null and address != ‘‘">
        and address like concat(‘%‘, #{address}, ‘%‘)
    </if>
</select>
mapper:
List<Map<String, Object>> getData(Map<String, Object> map);

service:
public List<Map<String, Object>> getData(Map<String, Object> map) {
    return mapper.getData(map);
}

controller:
@ResponseBody
@RequestMapping("/getData")
public List<Map<String, Object>> getData(@RequestBody Map<String, Object> map) {
    return service.getData(map);
}
js:
var params = {};
params.name = "张三";
params.address = "武汉";
$.ajax({
    url: "/ace/getData",
    type: "POST",
    data: JSON.stringify(params),
    contentType: "application/json",
    success:function(data){
        debugger
    }
});

技术分享图片

java之map作为参数和结果类型

原文:https://www.cnblogs.com/xxdjj/p/14473261.html

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!