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python小游戏——谁先数到100

时间:2021-03-27 09:10:40      阅读:35      评论:0      收藏:0      [点我收藏+]

逻辑还是要多练练的!

"""
小游戏:看谁先数到100
游戏规则:两个人轮流从1开始数数,每人每次数且只能数1到3个数,先数到100即为赢家
"""

print("  看谁先数到100  ".center(60,"*"))

def func(n, x, flag):
    """
    n:目标数
    x:步进值
    flag:计算机是否先出。先出为0,后出为1
    """
    count = 0
    y = x + 1  # 关键值
    if flag == 1:       # 人先出
        people_num = int(input())
        if not (people_num > 0 and people_num < y):
            print("你的输入有错误,你耍赖,不和你玩了。")
            exit()
        count = count + people_num
        print("人数 {} ,现在是 {}".format(people_num,count))
        n = n - people_num
    while True:
        if n % y == 0:
            computer_num = 1
            count = count + computer_num
            print("计算机数 {} ,现在是 {}".format(computer_num,count))
            people_num = int(input())
            if not (people_num > 0 and people_num < y):
                print("你的输入有错误,你耍赖,不和你玩了。")
                break
            count = count + people_num
            print("人数 {} ,现在是 {}".format(people_num,count))
            n = n - computer_num - people_num
            if n < y:
                print("计算机认输啦!你赢啦!!")
                break                
        elif n % y != 0:
            computer_num = n % y
            count = count + computer_num
            print("计算机数 {} ,现在是 {}".format(computer_num,count))
            people_num = int(input())
            if not (people_num > 0 and people_num < y):
                print("你的输入有错误,你耍赖,不和你玩了。")
                break
            count = count + people_num
            print("人数 {} ,现在是 {}".format(people_num,count))
            n = n - computer_num - people_num
            if n < y:
                print("很遗憾,你输了!!")
                break

func(100,3,1)

 

python小游戏——谁先数到100

原文:https://www.cnblogs.com/ooops/p/14584736.html

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