c语言中求4行3列数组元素的和

#include <stdio.h>

int main(void)
{
    int i, j;
    int a[4][3] = {{74,85,69},{14,25,36},{45,65,96},{58,47,56}};
    int b[4][3] = {{45,56,74},{25,14,36},{85,74,96},{25,74,85}};
    int c[4][3];
    
    for (i = 0; i < 4; i++)
    {
        for (j = 0; j < 3; j++)
        {
            c[i][j] = a[i][j] + b[i][j];
        }
    }
    puts("array1 :");
    for (i = 0; i < 4; i++)
    {
        for (j = 0; j < 3; j++)
        {
            printf("%3d", a[i][j]);
        }
        putchar(‘\n‘);
    }
    puts("arrar2 :");
    for (i = 0; i < 4; i++)
    {
        for (j = 0; j < 3; j++)
        {
            printf("%3d", b[i][j]);
        }
        putchar(‘\n‘);
    }
    puts("sum :");
    for (i = 0; i < 4; i++)
    {
        for (j = 0; j < 3; j++)
        {
            printf("%4d", c[i][j]);
        }
        putchar(‘\n‘);
    }
    return 0;
}