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1038. Binary Search Tree to Greater Sum Tree

时间:2021-03-28 11:39:07      阅读:21      评论:0      收藏:0      [点我收藏+]

Given the root of a Binary Search Tree (BST), convert it to a Greater Tree such that every key of the original BST is changed to the original key plus sum of all keys greater than the original key in BST.

As a reminder, a binary search tree is a tree that satisfies these constraints:

  • The left subtree of a node contains only nodes with keys less than the node‘s key.
  • The right subtree of a node contains only nodes with keys greater than the node‘s key.
  • Both the left and right subtrees must also be binary search trees.

Note: This question is the same as 538: https://leetcode.com/problems/convert-bst-to-greater-tree/

 

Example 1:

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Input: root = [4,1,6,0,2,5,7,null,null,null,3,null,null,null,8]
Output: [30,36,21,36,35,26,15,null,null,null,33,null,null,null,8]

Example 2:

Input: root = [0,null,1]
Output: [1,null,1]

Example 3:

Input: root = [1,0,2]
Output: [3,3,2]

Example 4:

Input: root = [3,2,4,1]
Output: [7,9,4,10]
 1 class Solution {
 2     int pre = 0;
 3     public TreeNode bstToGst(TreeNode root) {
 4         if (root.right != null) bstToGst(root.right);
 5         root.val = pre + root.val;
 6         pre = root.val;
 7         if (root.left != null) bstToGst(root.left);
 8         return root;
 9     }
10 }

 

1038. Binary Search Tree to Greater Sum Tree

原文:https://www.cnblogs.com/beiyeqingteng/p/14587720.html

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