/* *求1-100之和 */ function sum(num1, num2) { var num = num1 + num2; if (num2 + 1 > 100) { return num; } else { return sum(num, num2 + 1) } } var sum = sum(1, 2); console.log("sum ...",sum);
递归求1-100之和
原文：https://www.cnblogs.com/zhishiyv/p/14638267.html
