9 · Fizz Buzz 问题

描述
Given number n. Print number from 1 to n. According to following rules:

when number is divided by 3, print "fizz".
when number is divided by 5, print "buzz".
when number is divided by both 3 and 5, print "fizz buzz".
when number can‘t be divided by either 3 or 5, print the number itself.
样例
比如 n = 15, 返回一个字符串数组：

[
"1", "2", "fizz",
"4", "buzz", "fizz",
"7", "8", "fizz",
"buzz", "11", "fizz",
"13", "14", "fizz buzz"
]
挑战
你是否可以只用一个 if 来实现

答：不可以

class Solution:
    """
    @param n: An integer
    @return: A list of strings.
    """
    def fizzBuzz(self, n):
        res = []
        for i in range(1,n+1):
            if i%15 == 0:
                res.append("fizz buzz")
            elif i%3 == 0:
                res.append("fizz")
            elif i%5 == 0:
                res.append("buzz")
            else:
                res.append(str(i))
        return res

9 · Fizz Buzz 问题

原文：https://www.cnblogs.com/bernieloveslife/p/14638707.html