JsonConvert.DeserializeObject<T>(data);
报错：After parsing a value an unexpected character was encountered
错误原因是没有进行json转义
错误用法：return Json<T>(t); 输出未转义json
正确用法：return Json(JsonConvert.SerializeObject(t)); 输出转义后json
JsonConvert After parsing a value an unexpected character was encountered
原文：https://www.cnblogs.com/SolutionX/p/14645012.html