思路:
1.选择一个增量序列 t1,t2,……,tk,其中 ti > tj, tk = 1(最后必须是1)
2.按增量序列个数 k,对序列进行 k 趟排序
代码实现:
#include <iostream>
using namespace std;
template <typename T> //整數或浮點數皆可使用
void shell_sort(T* arr, int len, int* step, int steplen)
{
for (int i = 0; i < steplen; i++)
{
int perstep = step[i];
for (int j = perstep; j < len; j += perstep)
{
for (int k = j; k > 0; k -= perstep)
{
if (arr[k] < arr[k - perstep])
swap(arr[k], arr[k - perstep]);
else
break;
}
}
}
}
int main() {
int arr[] = { 61, 17, 29, 22, 34, 60, 72, 21, 50, 1, 62 };
int step[] = { 5 , 3, 1 };
int len = (int) sizeof(arr) / sizeof(*arr);
int steplen = (int) sizeof(step) / sizeof(*step);
shell_sort(arr, len, step, steplen);
for (int i = 0; i < len; i++)
cout << arr[i] << ‘ ‘;
cout << endl;
double arrf[] = { 17.5, 19.1, 0.6, 1.9, 10.5, 12.4, 3.8, 19.7, 1.5, 25.4, 28.6, 4.4, 23.8, 5.4 };
len = (int) sizeof(arrf) / sizeof(*arrf);
shell_sort(arrf, len, step, steplen);
for (int i = 0; i < len; i++)
cout << arrf[i] << ‘ ‘ << endl;
return 0;
}
原文:https://www.cnblogs.com/ming-fei/p/14660135.html