1.
#include <stdio.h> #include<stdlib.h> long long fun(int n); int main(){ int n; long long f; while (scanf("%d",&n)!= EOF){ f = fun(n); printf("n = %d, f = %lld\n", n, f); } system("pause"); return 0; } long long fun(int n){ long long s; if(n==1) s=1; else s=2*fun(n-1)+1; return s; }
2-1
#include <stdio.h> #include <stdlib.h> long long fac(int n); int main() { int i,n; printf("Enter n: "); scanf("%d", &n); for(i=1; i<=n; ++i) printf("%d! = %lld\n", i, fac(i)); system("pause"); return 0; } long long fac(int n) { static long long p = 1; p = p*n; return p; }
2-2
#include <stdio.h> #include <stdlib.h> int func(int,int); int main(){ int k=4,m=1,p1,p2; p1=func(k,m); p2=func(k,m); printf("%d,%d\n",p1,p2); system("pause"); return 0; } int func(int a,int b){ static int m=0,i=2; i+=m+1; m=i+a+b; return (m); }
小结:static在调用一次函数后,再次调用时会使用上次调用后的结果,不是一直固定不变的
4-3
#include <stdio.h> #include <stdlib.h> #define N 1000 int fun(int n,int m,int bb[N]) { int i,j,k=0,flag; for(j=n;j<=m;j++) { flag=j; for(i=2;i<j;i++) if(flag%i==0) { flag=0; break; } if(flag!=0) bb[k++]=j; } return k; } int main(){ int n=0,m=0,i,k,bb[N]; scanf("%d",&n); scanf("%d",&m); for(i=0;i<m-n;i++) bb[i]=0; k=fun(n,m,bb); for(i=0;i<k;i++) printf("%4d",bb[i]); return 0; }
4-4
#include <stdio.h> void dec2n(int x, int n); // 函数声明 int main() { int x; printf("输入一个十进制整数: "); scanf("%d", &x); dec2n(x, 2); dec2n(x, 8); dec2n(x, 16); return 0; } void dec2n(int x, int n) { int i,b,a[100]; for(i=0;x!=0;i++){ a[i]=x%n; x=x/n; } if(a[i]>9) switch(a[i]){ case 10:a[i]=‘A‘;break; case 11:a[i]=‘B‘;break; case 12:a[i]=‘C‘;break; case 13:a[i]=‘D‘;break; case 14:a[i]=‘E‘;break; case 15:a[i]=‘F‘;break; } printf("\n"); for(b=i-1;b>=0;b--){ printf("%d",a[b]); } }
原文:https://www.cnblogs.com/zhangxinyuaidaqiu/p/14719465.html