c语言中自定义函数计算x的n次方

#include <stdio.h>

int main(void)
{
    int i, x, n;
    int tmp = 1;
    puts("please input the values of x and n.");
    printf("x = "); scanf("%d", &x);
    printf("n = "); scanf("%d", &n);
    
    for(i = 1; i <= n; i++)
    {
        tmp *= x;
    }
    
    printf("the result ls: %d\n", tmp);
    return 0;
}

#include <stdio.h>

double power(double x, int n)
{
    double tmp = 1.0;
    int i;
    for(i = 1; i <= n; i++)
    {
        tmp *= x;
    }
    return tmp;
}

int main(void)
{
    double a; 
    int b;
    puts("please input double a and int b.");
    printf("a = "); scanf("%lf", &a);
    printf("b = "); scanf("%d", &b);
    
    printf("result: %.2f\n", power(a, b));
    return 0;
}

#include <stdio.h>

double power(double x, int n)
{
    double tmp = 1.0;
    
    while(n-- > 0)
    {
        tmp *= x;
    }
    return tmp;
}

int main(void)
{
    double a;
    int b;
    puts("please input double a and int b.");
    printf("a = "); scanf("%lf", &a);
    printf("b = "); scanf("%d", &b);
    
    printf("result: %.2f\n", power(a, b));
    return 0;
}