1、确定分界点:mid = (l + r) / 2
2、递归排序left, right
3、归并 合二为一
模板
注意l 和 1 的区分
#include<bits/stdc++.h> //万能头文件
using namespace std;
const int N = 1000010;
int n;
int q[N], tmp[N];
//模板
void merge_sort(int q[], int l, int r) {
if (l >= r) {
return;
}
int mid = l + r >> 1;
merge_sort(q, l, mid);
merge_sort(q, mid + 1, r);
int k = 0, i = l, j = mid + 1;
while (i <= mid && j <= r) {
if (q[i] <= q[j]) {
tmp[k++] = q[i++];
} else {
tmp[k++] = q[j++];
}
}
while (i <= mid) {
tmp[k++] = q[i++];
}
while (j <= r) {
tmp[k++] = q[j++];
}
for (i = l, j = 0; j <= r; i++, j++) {
q[i] = tmp[j];
}
}
int main() {
scanf("%d", &n);
for (int i = 0; i < n; i++) scanf("%d", &q[i]);
merge_sort(q, 0, n - 1);
for (int i = 0; i < n; i++) printf("%d ", q[i]);
return 0;
}
原文:https://www.cnblogs.com/mrmrwjk/p/14752798.html