判断奇偶数

1、按位与

　　select * from cinema WHERE id&1; 

2、id先除以2然后乘2 如果与原来的相等就是偶数

　　select * from cinema WHERE id=(id>>1)<<1; 

3、正则匹配最后一位

　　select * from cinema WHERE id regexp ‘[13579]$‘;
　　select * from cinema WHERE id regexp ‘[02468]$‘;

4、id计算

　　select * from cinema WHERE id%2 = 1;
　　select * from cinema WHERE id%2 = 0;

　　select * from cinema WHERE mod(id, 2) = 1;
　　select * from cinema WHERE mod(id, 2) = 0;

5、1的奇数次方和偶数次方

　　select * from cinema WHERE POWER(-1, id) = -1;
　　select * from cinema WHERE POWER(-1, id) = 1;

　　https://blog.csdn.net/zhazhagu/article/details/80452473

判断奇偶数

原文：https://www.cnblogs.com/wjq-/p/14755034.html