/** * Definition for a binary tree node. * function TreeNode(val, left, right) { * this.val = (val===undefined ? 0 : val) * this.left = (left===undefined ? null : left) * this.right = (right===undefined ? null : right) * } */ /** * @param {TreeNode} root * @param {number} x * @param {number} y * @return {boolean} */ var isCousins = function(root, x, y) { let tree = []; tree.push({node:root,level:0}); let p1=0,p2=0,h1=0,h2=0; while(tree.length>0){ cur = tree.shift(); if(cur.node.left && cur.node.left.val === x){ p1 = cur.node.val; h1 = cur.level; } if(cur.node.left && cur.node.left.val === y){ p2 = cur.node.val; h2 = cur.level; } if(cur.node.right && cur.node.right.val === x){ p1 = cur.node.val; h1 = cur.level; } if(cur.node.right && cur.node.right.val === y){ p2 = cur.node.val; h2 = cur.level; } if(p1 && p2 && h1 && h2 && p1!==p2 && h1===h2){ return true; } if(cur.node.left)tree.push({node:cur.node.left,level:cur.level+1}); if(cur.node.right)tree.push({node:cur.node.right,level:cur.level+1}); } return false; };
示例 1:
原文:https://www.cnblogs.com/yanjianjiang/p/14775782.html