说明: 定义一个10位数的数组,接受穿过来的5 ,就是原数组地1--1共5位 结束,然后取中间值,然后依次循环1.12--4,再去中间值,然后将新拿到的中间值,将原有数组 第5+1 位替换掉,生成一个新数组。 就这样:
1, 1.12, 0.9, 1.2, 1, 4, 1.1, 6, 0.9, 4 原数组
1, 1.12, 0.9, 1.2, 1,1,1.12,1.1,1.2,1.1 新数组
//首次从0开始,数组的首标自动+1; int zxh = 0; // 循环完一次后数组的尾标+1 int last = 0; //List<string> jstring = new List<string>; List<double> zws = new List<double>(); using (var db = new SecureCloud_Entities()) { //原数组 double[] myarray = { 1, 1.12, 0.9, 1.2, 1, 4, 1.1, 6, 0.9, 4 }; double[] newmyarray = new double[myarray.Length]; myarray.CopyTo(newmyarray,0); int length = myarray.Length; int a = 5; //传过来的值,到第几位结束 //最终循环次数 int cycles = length - a; List<double> windowPixelColorList = new List<double>(); double med; // int zzxh = length - a + 1; for (int i = zxh; i <= myarray.Length; i++) { if (zxh < cycles) { if (i <= a - 1 + last) // && { windowPixelColorList.Add(myarray[i]); windowPixelColorList.Sort(); //数组从0开始,满足6时进入取中位数 if (a - i + last == 1) { i = zxh; double[] list = windowPixelColorList.ToArray(); int count = list.Length; //判断中位数是偶数 if (count % 2 == 0) { med = (list[count / 2] + list[count / 2 - 1]) / 2d; } else { //中位数奇数 med = list[count / 2]; } // newmyarray[a + last] = med; zws.Add(med); zxh++; windowPixelColorList = new List<double>(); last++; } } } else { break; } } Console.WriteLine(" {0}", zws.ToString()); //原来的数据 Console.WriteLine(" {0}", newmyarray.ToString()); //改变后的数据 } return ;
原文:https://www.cnblogs.com/lvqianqian/p/14812369.html