[SQL] 用标准SQL实现 DENSE_RANK() 和 RANK() 函数

create table test_order(
 name varchar2(100),    -- 名称
 id   int               -- 加入编号
);

insert into test_order values(‘CAA‘, 100);
insert into test_order values(‘CAB‘, 80);
insert into test_order values(‘CAC‘, 80);
insert into test_order values(‘CAD‘, 70);
insert into test_order values(‘CAE‘, 60);
commit ; 


select name, id, rank() over(order by id), dense_rank() over(order by id )
from test_order ;

select name
       ,id
       ,(select count(id) from test_order b where a.id > b.id) + 1          as DENSE_RANK
       ,(select count(distinct id) from test_order b where a.id > b.id) + 1 as RANK
from test_order a 
order by id 
;