信号灯法

package cn.ruhsang.gaoji;

//测试生产者消费者的问题2:信号灯法,标志位解决
public class TestPC2 {
    public static void main(String[] args) {
        TV tv = new TV();
        new Player(tv).start();
        new Watcher(tv).start();
    }

}
//生产者-->演员
class Player extends Thread{
    TV tv;
    public Player(TV tv){
        this.tv = tv;
    }

    @Override
    public void run() {
        for (int i = 0; i < 20; i++) {
            if(i%2==0){
                this.tv.play("快乐大本营播放中");
            }else {
                this.tv.play("抖音:记录美好生活");
            }
        }
    }
}

//消费者-->观众
class Watcher extends Thread{
    TV tv;
    public Watcher(TV tv){
        this.tv = tv;
    }

    @Override
    public void run() {
        for (int i = 0; i < 20; i++) {
            tv.watch();
        }
    }
}

//产品-->节目
class TV{
    //演员表演,观众等待  true
    //观众看时演员等待   false
    String voice;//表演的节目
    boolean flag = true;//标志位
    //演员表演
    public synchronized void play(String voice){
        if(!flag){
            try {
                this.wait();
            } catch (InterruptedException e) {
                e.printStackTrace();
            }
        }
        System.out.println("演员表演了:"+voice);
        //通知观众观看
        this.notifyAll();//通知唤醒
        //通知观众可以看了
        this.voice = voice;
        this.flag = !this.flag;
    }

    //观众看
    public synchronized void watch(){
        if(flag){
            try {
                this.wait();
            } catch (InterruptedException e) {
                e.printStackTrace();
            }
        }
        System.out.println("观众观看了:"+voice);
        //通知演员表演
        this.notifyAll();
        this.flag = !this.flag;
    }
}

信号灯法

原文：https://www.cnblogs.com/nigustudent/p/14876108.html