366. Find Leaves of Binary Tree

时间：2021-07-03 10:52:16 阅读：24 评论：0 收藏：0 [点我收藏+]

Given a binary tree, collect a tree‘s nodes as if you were doing this: Collect and remove all leaves, repeat until the tree is empty.

Example:
Given binary tree

          1
         /         2   3
       / \     
      4   5

Returns [4, 5, 3], [2], [1].

Explanation:

1. Removing the leaves [4, 5, 3] would result in this tree:

          1
         / 
        2

2. Now removing the leaf [2] would result in this tree:

3. Now removing the leaf [1] would result in the empty tree:

[]

Returns [4, 5, 3], [2], [1].

https://zhuhan0.blogspot.com/2017/05/leetcode-366-find-leaves-of-binary-tree.html

https://www.youtube.com/watch?v=2vwTmHTL1Mk&ab_channel=XavierElon

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这题还比较新（对我），解决办法是计算每个node的height，子节点是0，网上走，root = Math。max（left，right）+ 1。root==null就返回-1.

然后看是否需要加入新的ArrayList，然后把相同height的node加到对应的list中

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原文：https://www.cnblogs.com/wentiliangkaihua/p/14965487.html

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