使用 ruamel.yaml 读写 yaml 文档，解决16进制混搭10进制数据读出来全是10进制

import ruamel.yaml


class LaoLiuNiuBiVersionedResolver(ruamel.yaml.SafeLoader):
    def __init__(self, *args, **kwargs):
        super(LaoLiuNiuBiVersionedResolver, self).__init__(*args, **kwargs)
        self.yaml_constructors[‘tag:yaml.org,2002:hex‘] = self.parser_hex

    def parser_hex(self, _, node):

        return node.value

    def resolve(self, kind, value, implicit):

        if value and value.startswith(‘0x‘):
            return ‘tag:yaml.org,2002:hex‘
        else:
            return super(LaoLiuNiuBiVersionedResolver, self).resolve(kind, value, implicit)


data = ruamel.yaml.load("""
x: 42
a: 0x2a
z: 0o52
""", Loader=LaoLiuNiuBiVersionedResolver)

print(data, )

import ruamel.yaml
from ruamel import yaml
import sys
import json
from ruamel.yaml.scalarint import ScalarInt, BinaryInt, OctalInt, HexInt, HexCapsInt
with open(‘faucet.yaml‘,"r") as f:
    a = yaml.round_trip_load(f)
    f.close()

a["acls"]["system"][0]["rule"]["eth_type"] = HexInt(100)
with open(‘faucet.yaml‘, ‘w‘) as nf:
    yaml.round_trip_dump(a, nf, Dumper=yaml.RoundTripDumper)
    nf.close()


# print(HexInt(300),type(HexInt(300)))