17. Merge Two Binary Trees 融合二叉树

［抄题］：

Given two binary trees and imagine that when you put one of them to cover the other, some nodes of the two trees are overlapped while the others are not. 

You need to merge them into a new binary tree. The merge rule is that if two nodes overlap, then sum node values up as the new value of the merged node. Otherwise, the NOT null node will be used as the node of new tree.

Example 1:

Input: 
	Tree 1                     Tree 2                  
          1                         2                             
         / \                       / \                            
        3   2                     1   3                        
       /                           \   \                      
      5                             4   7                  
Output: 
Merged tree:
	     3
	    / 	   4   5
	  / \   \ 
	 5   4   7

复习了还是不会的地方：这有关于左右形状的题递归还要考虑左右啊

/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode() {}
 *     TreeNode(int val) { this.val = val; }
 *     TreeNode(int val, TreeNode left, TreeNode right) {
 *         this.val = val;
 *         this.left = left;
 *         this.right = right;
 *     }
 * }
 */
class Solution {
    public TreeNode mergeTrees(TreeNode t1, TreeNode t2) {
        if (t1 == null) return t2;
        if (t2 == null) return t1;
        
        TreeNode mergedNode = new TreeNode();
        mergedNode.val = t1.val + t2.val;
        mergedNode.left = mergeTrees(t1.left, t2.left);
        mergedNode.right = mergeTrees(t1.right, t2.right);
        
        return mergedNode;
    }
}

17. Merge Two Binary Trees 融合二叉树

原文：https://www.cnblogs.com/immiao0319/p/14979742.html