public class ArrayDemo08 {
public static void main(String[] args) {
/*
1.创建一个二位数组 11*11 0,没有棋子 1 黑棋 2 白棋
*/
int [][] array1= new int[11][11];
array1[1][2] = 1;
array1[2][3] = 2;
//输出原始数组
System.out.println("输出原始数组:");
for (int[] ints : array1) { // array1.for 回车
for (int anInt : ints) {
System.out.print(anInt+"\t");
}
System.out.println();
}
System.out.println("===========================");
//转换为稀疏数组保存
//获取有效值个数
int sum = 0;
for (int i = 0; i < 11; i++) {
for (int j = 0; j < 11; j++) {
if (array1[i][j]!=0){
sum++;
}
}
}
System.out.println("有效数值的个数:"+sum);
//2.创建一个稀疏数组
int[][] array2 = new int[sum+1][3];
array2[0][0] = 11;
array2[0][1] = 11;
array2[0][2] = sum;
//遍历二维数组,将非零的数值,存放在稀疏数组中
int count=0;
for (int i = 0; i < array1.length; i++) {
for (int j = 0; j < array1[i].length; j++) {
if (array1[i][j]!=0){
count++;
array2[count][0]=i;
array2[count][1]=j;
array2[count][2]=array1[i][j];
}
}
}
//输出稀疏数组
System.out.println("稀疏数组");
for (int i = 0; i < array2.length; i++) {
System.out.println(array2[i][0]+"\t"
+array2[i][1]+"\t"
+array2[i][2]+"\t");
}
System.out.println("===========================");
System.out.println("还原");
//1.读取稀疏数组
int[][] array3 = new int[array2[0][0]][array2[0][1]];
//2.给其中元素还原值
for (int i = 1; i < array2.length; i++) {
array3[array2[i][0]][array2[i][1]] = array2[i][2];
}
//3.打印
System.out.println("输出还原数组值:");
for (int[] ints : array3) { // array1.for 回车
for (int anInt : ints) {
System.out.print(anInt + "\t");
}
System.out.println();
}
}
}
原文:https://www.cnblogs.com/ariesmark/p/15096451.html