双重for循环简化

let permission = [
      {id:1},
      {id:2},
      {id:3}
    ]
let menuList = [
      {id:1},
      {id:4},
      {id:5},
      {id:6}
    ]

let saveData = []
for (let i = 0; i < permission.length; i++) {
    for (let j = 0; j < menuList.length; j++) {
        if(permission[i].id == menuList[j].id)
        saveData.push(permission[i].id)
    }
}
console.log(saveData,‘saveData‘);

const temp = permission.reduce((r,v) => (r[v.id] = true,r),{})
let aaa = menuList.filter(v => temp[v.id]).map(v => v.id)

const permissionId = permission.filter(v => menuList.some(s => v.id == s.id)).map(r => r.id)