//去重复
unique(arr1) {
const res = new Map();
return arr1.filter((a) => !res.has(a.level) && res.set(a.level, 1))
},
uniqueFun(arr, type) {
const res = new Map();
return arr.filter((a) => !res.has(a[type]) && res.set(a[type], 1));
}
原文:https://www.cnblogs.com/linhan8888/p/15226306.html