# P2911 [USACO08OCT]Bovine Bones G 牛骨头

## 题目描述

Bessie loves board games and role-playing games so she persuaded Farmer John to drive her to the hobby shop where she purchased three dice for rolling. These fair dice have S1, S2, and S3 sides

respectively (2 <= S1 <= 20; 2 <= S2 <= 20; 2 <= S3 <= 40).

Bessie rolls and rolls and rolls trying to figure out which three-dice sum appears most often.

Given the number of sides on each of the three dice, determine which three-dice sum appears most frequently. If more than one sum can appear most frequently, report the smallest such sum.

POINTS: 70

## 输入格式

• Line 1: Three space-separated integers: S1, S2, and S3

## 输出格式

• Line 1: The smallest integer sum that appears most frequently when the dice are rolled in every possible combination.

3 2 3 5

## 说明/提示

Here are all the possible outcomes.

1 1 1 -> 3
1 2 1 -> 4
2 1 1 -> 4
2 2 1 -> 5
3 1 1 -> 5
3 2 1 -> 6
1 1 2 -> 4
1 2 2 -> 5
2 1 2 -> 5
2 2 2 -> 6
3 1 2 -> 6
3 2 2 -> 7
1 1 3 -> 5
1 2 3 -> 6
2 1 3 -> 6
2 2 3 -> 7
3 1 3 -> 7
3 2 3 -> 8

Both 5 and 6 appear most frequently (five times each), so 5 is the answer.

## 解答

``````#include<bits/stdc++.h>
using namespace std;

int main()
{
int s1,s2,s3,c=0,s=0;
cin>>s1>>s2>>s3;
int a[s1+s2+s3+1]={0};
for(int i=1;i<=s1;i++)
{
for(int j=1;j<=s2;j++)
{
for(int k=1;k<=s3;k++)
{
a[i+j+k]++;
if(a[i+j+k]>c)
{
c=a[i+j+k];
s=i+j+k;
}
}
}
}
cout<<s;
return 0;
}
``````

P2911 [USACO08OCT]Bovine Bones G 牛骨头

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