2 3 2 1 2 10 3 1 15 1 2 2 3 2 2 1 2 100 1 2 2 1
10 25 100 100
#include <iostream>
#include <cstring>
#include <vector>
#include <cstdio>
using namespace std;
const int M = 4 * 1e4 + 100;
typedef long long ll;
typedef pair<int,int> P;
vector<P>G[M];
int vis[M],isGO,e;
void dfs(int x, int cost)
{
if(isGO || vis[x]) return ;
if(x == e)//数据太大,要改成全局变量
{
isGO = 1;
printf("%d\n",cost);
return ;
}
vis[x] = 1;
for(int i = 0; i < G[x].size(); i++)
{
P a = G[x][i];
dfs(a.first,cost + a.second);
}
vis[x] = 0;
}
void solve()
{
int x,y,c,n,m;
scanf("%d %d",&n,&m);
for(int i = 1; i < n; i++)
{
scanf("%d %d %d",&x,&y,&c);
G[x].push_back(make_pair(y,c));
G[y].push_back(make_pair(x,c));
}
while(m--)
{
isGO = 0;
scanf("%d %d",&x,&e);
dfs(x,0);
}
for(int i = 1; i <= n; i++) G[i].clear();
}
int main()
{
int T,cnt = 0;
scanf("%d",&T);
while(T--)
{
solve();
}
return 0;
}
原文:http://blog.csdn.net/zsgg_acm/article/details/39717533