解析LOOKUP函数

#include<iostream>
using namespace std;
int loopup(int x[],int n,int y)
{
	int flag=-1;
	for(int i=0;i<n;i++)
		if(x[i]==y) {flag=i;break;}
	return flag;
}
void main()
{
	int n;
	cout<<"n:"; cin>>n;
	int *x=new int[n];
	for(int i=0;i<n;i++)
		cin>>*(x+i);
	int y;
	cout<<"y:"; cin>>y;
	int flag1=loopup(x,n,y);
	if(flag1==-1) cout<<"NO EXIST!"<<endl;
	else cout<<"Number:"<<flag1<<endl;
}