f(i-1,j-1)+1 (a[i]==b[j])
f(i,j)= {
max(f(i-1,j),f(i,j-1)) (a[i]!=b[j])
#include<stdio.h>
#include<string.h>
int dp[1000][1000];
int max(int a,int b)
{
return a=a>b?a:b;
}
int main()
{
char s1[1000],s2[1000];
while(scanf("%s%s",s1+1,s2+1)!=EOF)
{
memset(dp,0,sizeof(dp));
int i=0;
int j=0;
for(i=1;s1[i]!=‘\0‘;i++)
{
for(j=1;s2[j]!=‘\0‘;j++)
{
if(s1[i]==s2[j])
{
dp[i][j]=dp[i-1][j-1]+1;
}
else
{
dp[i][j]=max(dp[i-1][j],dp[i][j-1]);
}
}
}
printf("%d\n",dp[i-1][j-1]);
}
}hdu 1059 Common Subsequence动态规划
原文:http://blog.csdn.net/cnh294141800/article/details/19568595