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LeetCode Merge Sorted Array

时间:2014-10-06 11:50:30      阅读:212      评论:0      收藏:0      [点我收藏+]

Given two sorted integer arrays A and B, merge B into A as one sorted array.

Note:
You may assume that A has enough space (size that is greater or equal to m + n) to hold additional elements from B. The number of elements initialized in A and B are m and n respectively.

 

 1 public class Solution {
 2     public void merge(int A[], int m, int B[], int n) {
 3         int[] newA=new int[m+n];
 4         int indexA = 0,indexB=0;
 5         int i=0;
 6         while (indexA<m && indexB<n) {
 7             if (A[indexA]<B[indexB]) {
 8                 newA[i]=A[indexA];
 9                 indexA++;
10             }else {
11                 newA[i]=B[indexB];
12                 indexB++;
13             }
14             ++i;
15         }
16         if (indexA==m) {
17             for (int j = indexB; j < n; j++) {
18                 newA[i]=B[j];
19                 ++i;
20             }
21         }
22         if (indexB==n) {
23             for (int j = indexA; j < m; j++) {
24                 newA[i]=A[j];
25                 ++i;
26             }
27         }
28         
29         for (int j = 0; j < m+n; j++) {
30             A[j]=newA[j];
31         }
32         
33     }
34 }

 

LeetCode Merge Sorted Array

原文:http://www.cnblogs.com/birdhack/p/4008022.html

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