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每天一个JavaScript实例-递归实现反转数组字符串

时间:2014-10-14 12:50:09      阅读:316      评论:0      收藏:0      [点我收藏+]
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<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<title>每天一个JavaScript实例-递归实现反转数组字符串</title>
<script>
var func = function(x,indx,str){
	return indx == 0 ? str : func(x,--indx,(str +=" " + x[indx]));;
	}
var arr = new Array("apple","banna","orange","apple2","apple3");
var arr1 = arr.slice(0)
var arr3 = func(arr1,arr1.length,"");
var arr2 = arr.slice(0).reverse();
console.log(arr2);
console.log(arr);
console.log(arr3);

</script>
</head>

<body>

<div id = "date">
</div>

</body>
</html>

每天一个JavaScript实例-递归实现反转数组字符串

原文:http://blog.csdn.net/waiting7436/article/details/40073649

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