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sort algorithm

时间:2014-10-17 04:43:54      阅读:434      评论:0      收藏:0      [点我收藏+]

insert sort:

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merge sort:

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其实很像后续遍历.

package com.java2novice.sorting;
 
public class MyMergeSort {
     
    private int[] array;
    private int[] tempMergArr;
    private int length;
 
    public static void main(String a[]){
         
        int[] inputArr = {45,23,11,89,77,98,4,28,65,43};
        MyMergeSort mms = new MyMergeSort();
        mms.sort(inputArr);
        for(int i:inputArr){
            System.out.print(i);
            System.out.print(" ");
        }
    }
     
    public void sort(int inputArr[]) {
        this.array = inputArr;
        this.length = inputArr.length;
        this.tempMergArr = new int[length];
        doMergeSort(0, length - 1);
    }
 
    private void doMergeSort(int lowerIndex, int higherIndex) {
         
        if (lowerIndex < higherIndex) {
            int middle = lowerIndex + (higherIndex - lowerIndex) / 2;
            // Below step sorts the left side of the array
            doMergeSort(lowerIndex, middle);
            // Below step sorts the right side of the array
            doMergeSort(middle + 1, higherIndex);
            // Now merge both sides
            mergeParts(lowerIndex, middle, higherIndex);
        }
    }
 
    private void mergeParts(int lowerIndex, int middle, int higherIndex) {
 
        for (int i = lowerIndex; i <= higherIndex; i++) {
            tempMergArr[i] = array[i];
        }
        int i = lowerIndex;
        int j = middle + 1;
        int k = lowerIndex;
        while (i <= middle && j <= higherIndex) {
            if (tempMergArr[i] <= tempMergArr[j]) {
                array[k] = tempMergArr[i];
                i++;
            } else {
                array[k] = tempMergArr[j];
                j++;
            }
            k++;
        }
        // left always longer than right.
        while (i <= middle) {
            array[k] = tempMergArr[i];
            k++;
            i++;
        }
 
    }
}

 

sort algorithm

原文:http://www.cnblogs.com/leetcode/p/4030115.html

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