# The series, 11 + 22 + 33 + ... + 1010 = 10405071317.
# Find the last ten digits of the series, 11 + 22 + 33 + ... + 10001000.
import time
start = time.time()
print "last ten digits was %s and cost %s seconds" % (str(sum([i**i for i in range(1, 1001)]))[-10:], time.time() - start)
Euler Project question 48 in python way
原文：http://www.cnblogs.com/cyberpaz/p/4035434.html