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Same Tree 判断相同树

时间:2014-10-27 08:07:18      阅读:256      评论:0      收藏:0      [点我收藏+]

Given two binary trees, write a function to check if they are equal or not.

Two binary trees are considered equal if they are structurally identical and the nodes have the same value.

 

判断两棵树是否相同和之前的判断两棵树是否对称都是一样的原理,利用深度优先搜索DFS来递归。代码如下:

 

/**
 * Definition for binary tree
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
public:
    bool isSameTree(TreeNode *p, TreeNode *q) {
        if (!p && !q) return true;
        if ((p && !q) || (!p && q) || (p->val != q->val)) return false;
        return isSameTree(p->left, q->left) && isSameTree(p->right, q->right);
    }
};

 

Same Tree 判断相同树

原文:http://www.cnblogs.com/grandyang/p/4053384.html

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