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OpenCL案例研究之一<矩阵乘法>

时间:2014-02-25 12:56:40      阅读:954      评论:0      收藏:0      [点我收藏+]


一、案例简述


  本案例讲述使用OpenCL计算矩阵乘法:C = A * B 。

  设A、B、C分别是大小为N*P、P*M和N*M的矩阵,那么顺序实现的C代码可以如下所示:

 // C Function
void mat_mul(
			 int Ndim, int Mdim, int Pdim,
			 float* A, float* B, float* C)
{
    int i, j, k;
	float tmp;

	for (i = 0; i < Ndim; i++) {
		for (j = 0; j < Mdim; j++) {
			tmp = 0.0;
			for (k = 0; k < Pdim; k++)
				tmp += A[i*Pdim + k] * B[k*Mdim + j];
			C[i*Mdim + j] = tmp;
		}
	}
}


二、OpenCL实现矩阵乘法


1. 内核函数实现

 // OpenCL Kernel Function
__kernel void HelloOpenCL(
						  const int Ndim,
						  const int Mdim,
						  const int Pdim,
						  __global const float* A, 
						  __global const float* B, 
						  __global float* C)
{
    int i = get_global_id(0);
	int j = get_global_id(1);

	int k;
	float tmp;

	if ((i < Ndim) && (j < Mdim)) {
		tmp = 0.0;
		for (k = 0; k < Pdim; k++)
			tmp += A[i*Pdim + k] * B[k*Mdim + j];
		C[i*Mdim + j] = tmp;
	}
}
  为每个工作项分配一个要计算的乘法矩阵的元素。将针对i,j的外层循环删除,替换为函数调用,查找两维中对应工作项的全局ID。要特别当心必须保证得到的工作项ID在矩阵C的范围内。这三个矩阵都留全局内存

2. 宿主机代码实现


  下面是在《基于CUDA的OpenCL开发环境搭建与入门程序示例》中main.cpp宿主机代码为基础的补丁文件。测量运行时间的部分:首先,在clCreateCommandQueue()函数中设置CL_QUEUE_PROFILING_ENABLE标志;然后,在clEnqueueNDRangeKernel()函数中设置事件对象;最后,通过clGetEventProfilingInfo()函数获取命令入队时间和命令执行结束时间。注意:时间的单位是纳秒,在最后打印时转换为秒显示。

--- /root/Desktop/main.cpp
+++ /root/Desktop/main_new.cpp
@@ -143,8 +143,10 @@
 	}
 
 	// 4. Choose the first device
-	commandQueue = clCreateCommandQueue(context,
-										devices[0], 0, NULL);
+	commandQueue = clCreateCommandQueue(context, 
+										devices[0], 
+										CL_QUEUE_PROFILING_ENABLE, 
+										NULL);
 	if (commandQueue == NULL) {
 		perror("Failed to create commandQueue for device 0.");
 		exit(1);
@@ -183,14 +185,33 @@
 
 
 	/******** 第四部分 创建内核和内存对象 ********/
-	#define ARRAY_SIZE 10
+	const int Ndim = 3;
+	const int Mdim = 4;
+	const int Pdim = 5;
+
+	int szA = Ndim * Pdim;
+	int szB = Pdim * Mdim;
+	int szC = Ndim * Mdim;
 
 	cl_kernel kernel = 0;
 	cl_mem memObjects[3] = {0, 0, 0};
 
-	float a[ARRAY_SIZE];
-	float b[ARRAY_SIZE];
-	float result[ARRAY_SIZE];
+	float *A;
+	float *B;
+	float *C;
+
+	A = (float *)malloc(szA * sizeof(float));
+	B = (float *)malloc(szB * sizeof(float));
+	C = (float *)malloc(szC * sizeof(float));
+
+	int i, j;
+
+	for (i = 0; i < szA; i++)
+		A[i] = i + 1;
+
+	for (i = 0; i < szB; i++)
+		B[i] = i + 1;
+
 
 	// 8. Create the kernel
     kernel = clCreateKernel(program, "HelloOpenCL", NULL);
@@ -200,23 +221,18 @@
 	}
 
 	// 9. Create memory objects
-	for (int i = 0; i < ARRAY_SIZE; i++) {
-		a[i] = (float)i + 1;
-		b[i] = (float)i + 1;
-	}
-
 	memObjects[0] = clCreateBuffer(context, CL_MEM_READ_ONLY |
 								   CL_MEM_COPY_HOST_PTR,
-								   sizeof(float) * ARRAY_SIZE,
-								   a, NULL);
+								   sizeof(float) * szA,
+								   A, NULL);
 	memObjects[1] = clCreateBuffer(context, CL_MEM_READ_ONLY |
 								   CL_MEM_COPY_HOST_PTR,
-								   sizeof(float) * ARRAY_SIZE,
-								   b, NULL);
+								   sizeof(float) * szB,
+								   B, NULL);
 	memObjects[2] = clCreateBuffer(context, CL_MEM_READ_WRITE |
 								   CL_MEM_COPY_HOST_PTR,
-								   sizeof(float) * ARRAY_SIZE,
-								   result, NULL);
+								   sizeof(float) * szC,
+								   C, NULL);
 	if (memObjects[0] == NULL || memObjects[1] == NULL || 
 			memObjects[2] == NULL) {
 		perror("Error in clCreateBuffer.\n");
@@ -225,48 +241,98 @@
 
 
 	/******** 第五部分 执行内核 ********/
-	size_t globalWorkSize[1] = { ARRAY_SIZE };
-	size_t localWorkSize[1] = { 1 };
 
 	// 10. Set the kernel arguments
-	errNum = clSetKernelArg(kernel, 0, sizeof(cl_mem), &memObjects[0]);
-    errNum |= clSetKernelArg(kernel, 1, sizeof(cl_mem), &memObjects[1]);
-    errNum |= clSetKernelArg(kernel, 2, sizeof(cl_mem), &memObjects[2]);
+	errNum = clSetKernelArg(kernel, 0, sizeof(int), &Ndim);
+    errNum |= clSetKernelArg(kernel, 1, sizeof(int), &Mdim);
+    errNum |= clSetKernelArg(kernel, 2, sizeof(int), &Pdim);
+	errNum |= clSetKernelArg(kernel, 3, sizeof(cl_mem), &memObjects[0]);
+    errNum |= clSetKernelArg(kernel, 4, sizeof(cl_mem), &memObjects[1]);
+    errNum |= clSetKernelArg(kernel, 5, sizeof(cl_mem), &memObjects[2]);
 	if (errNum != CL_SUCCESS) {
 		perror("Error in clSetKernelArg.\n");
         exit(1);
 	}
 
 	// 11. Queue the kernel up for execution across the array
-	errNum = clEnqueueNDRangeKernel(commandQueue, kernel, 1, NULL,
-									globalWorkSize, localWorkSize,
-									0, NULL, NULL);
+	size_t global[2];
+	cl_event prof_event;
+	cl_ulong ev_start_time = (cl_ulong)0;
+	cl_ulong ev_end_time = (cl_ulong)0;
+	double rum_time;
+
+	global[0] = (size_t)Ndim;
+	global[1] = (size_t)Mdim;
+
+	errNum = clEnqueueNDRangeKernel(commandQueue, kernel, 2, NULL,
+									global, NULL, 0, NULL, &prof_event);
 	if (errNum != CL_SUCCESS) {
 		perror("Error in clEnqueueNDRangeKernel.\n");
         exit(1);
 	}
 
+	clFinish(commandQueue);
+	errNum = clWaitForEvents(1, &prof_event);
+	if (errNum != CL_SUCCESS) {
+		perror("Error in clWaitForEvents.\n");
+        exit(1);
+	}
+
+	errNum = clGetEventProfilingInfo(prof_event,
+									 CL_PROFILING_COMMAND_QUEUED,
+									 sizeof(cl_ulong),
+									 &ev_start_time,
+									 NULL);
+
+	errNum |= clGetEventProfilingInfo(prof_event,
+									 CL_PROFILING_COMMAND_END,
+									 sizeof(cl_ulong),
+									 &ev_end_time,
+									 NULL);
+
+	if (errNum != CL_SUCCESS) {
+		perror("Error in clGetEventProfilingInfo.\n");
+		while(1);
+        exit(1);
+	}
+	
 	// 12. Read the output buffer back to the Host
 	errNum = clEnqueueReadBuffer(commandQueue, memObjects[2],
 								 CL_TRUE, 0,
-								 ARRAY_SIZE * sizeof(float), result,
+								 sizeof(float) * szC, C,
 								 0, NULL, NULL);
 	if (errNum != CL_SUCCESS) {
 		perror("Error in clEnqueueReadBuffer.\n");
         exit(1);
 	}
 
+	rum_time = (double)(ev_end_time - ev_start_time);
+
 
 	/******** 第六部分 测试结果 ********/
-	printf("\nTest: a * b = c\n\n");
-
-	printf("Input numbers:\n");
-	for (int i = 0; i < ARRAY_SIZE; i++)
-		printf("a[%d] = %f, b[%d] = %f\n", i, a[i], i, b[i]);
-
-	printf("\nOutput numbers:\n");
-	for (int i = 0; i < ARRAY_SIZE; i++)
-		printf("a[%d] * b[%d] = %f\n", i, i, result[i]);
+	
+	printf("\nArray A:\n");
+	for (i = 0; i < Ndim; i++) {
+		for (j = 0; j < Pdim; j++)
+			printf("%.3f\t", A[i*Pdim + j]);
+		printf("\n");
+	}
+
+	printf("\nArray B:\n");
+	for (i = 0; i < Pdim; i++) {
+		for (j = 0; j < Mdim; j++)
+			printf("%.3f\t", B[i*Mdim + j]);
+		printf("\n");
+	}
+
+	printf("\nArray C:\n");
+	for (i = 0; i < Ndim; i++) {
+		for (j = 0; j < Mdim; j++)
+			printf("%.3f\t", C[i*Mdim + j]);
+		printf("\n");
+	}
+	
+	printf("\n\nRunning Time:  %f s\n", rum_time*1.0e-9);
 
 	while(1);
 

3. 运行结果


  (1). N = 3,M = 4,P = 5。

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  (2). N = 1000,M = 1000,P = 1000。

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OpenCL案例研究之一<矩阵乘法>

原文:http://blog.csdn.net/cloud_desktop/article/details/19822025

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