求二叉数的深度和宽度

        二叉树的深度：二叉树的根结点所在的层数为1，根结点的孩子结点所在的层数为2，以此下去。深度是指所有结点中最深的结点所在的层数。

        二叉树的宽度：所有深度中含有的最多的子叶数。

        参考文献：http://blog.csdn.net/htyurencaotang/article/details/12406223#comments

        1.C++

//求二叉树的深度
int GetDepth(tagBiNode *pRoot)
{
	if (pRoot == NULL)
	{
		return 0;
	}

	// 	int nLeftLength = GetDepth(pRoot->m_left);
	// 	int nRigthLength = GetDepth(pRoot->m_right);
	// 	return nLeftLength > nRigthLength ? (nLeftLength + 1) : (nRigthLength + 1);

	return GetDepth(pRoot->left) > GetDepth(pRoot->right) ? 
		(GetDepth(pRoot->left) + 1) : (GetDepth(pRoot->right) + 1);
}

//求二叉树的宽度
int GetWidth(tagBiNode *pRoot)
{
	if (pRoot == NULL)
	{
		return 0;
	}

	int nLastLevelWidth = 0;//记录上一层的宽度
	int nTempLastLevelWidth = 0;
	int nCurLevelWidth = 0;//记录当前层的宽度
	int nWidth = 1;//二叉树的宽度
    queue<BiNode *> myQueue;
	myQueue.push(pRoot);//将根节点入队列
	nLastLevelWidth = 1;	
	tagBiNode *pCur = NULL;

	while (!myQueue.empty())//队列不空
	{
		nTempLastLevelWidth = nLastLevelWidth;
		while (nTempLastLevelWidth != 0)
		{
            pCur = myQueue.front();//取出队列头元素
			myQueue.pop();//将队列头元素出对

			if (pCur->left != NULL)
			{
				myQueue.push(pCur->left);
			}

			if (pCur->right != NULL)
			{
				myQueue.push(pCur->right);
			}

			nTempLastLevelWidth--;
		}

		nCurLevelWidth = myQueue.size();
		nWidth = nCurLevelWidth > nWidth ? nCurLevelWidth : nWidth;
		nLastLevelWidth = nCurLevelWidth;
	}

	return nWidth;
}

	public static int getHeight(BiNode head)
	{
		int deep = 0;
		if(head != null)
		{
			int left = getHeight(head.left);
			int right = getHeight(head.right);
			deep = (left>=right)?(left+1):(right+1);
		}
		return deep;
	}
	public static int getWidth(BiNode head)
	{
		if(head == null)
		{
			return 0;
		}
		
		int nWidth = 0;
		int nLastLevelWidth = 0;
		int nTempLastLevelWidth = 0;
		int nCurLevelWidth = 0; 
		
		Queue<BiNode> myQueue = new LinkedList<Demo.BiNode>();
		myQueue.add(head);
		nLastLevelWidth = 1;
		nWidth = 1;
		
		while(!myQueue.isEmpty())
		{
			nTempLastLevelWidth = nLastLevelWidth;
			BiNode tmp = null;
			while(nTempLastLevelWidth != 0)
			{
				tmp = myQueue.peek();
				myQueue.poll();

				if(tmp.left != null)
				{
					myQueue.add(tmp.left);
				}
				if(tmp.right != null)
				{
					myQueue.add(tmp.right);
				}
				nTempLastLevelWidth--;
			}
			
			nCurLevelWidth = myQueue.size();
			nWidth = nCurLevelWidth>nWidth?nCurLevelWidth:nWidth;
			nLastLevelWidth = nCurLevelWidth;
		}
		return nWidth;
	}

求二叉数的深度和宽度

原文：http://blog.csdn.net/conanswp/article/details/19831129