Time
Limit: 4000/2000 MS (Java/Others) Memory Limit:
131070/65535 K (Java/Others)
Total Submission(s):
15521 Accepted Submission(s):
6640
#include<iostream>
#include<stdio.h>
#include<string.h>
#include<stdlib.h>
using
namespace std;
struct dictree
{
struct dictree
*child[26];
int n;
};
struct dictree *root;
void
insert(char *source)
{
int i,j;
int len,id;
struct dictree
*current,*newnode;
len=strlen(source);
current=root;
for(i=0; i<len; i++)
{
id=source[i]-‘a‘;
if(current->child[id]!=0)
{
current=current->child[id];
current->n++;
}
else
{
newnode=(struct dictree *)malloc(sizeof(struct
dictree));
for(j=0; j<26;
j++)
newnode->child[j]=0;
current->child[id]=newnode;
current=newnode;
current->n=1;
}
}
}
int find(char
*source)
{
int i,id;
int
len;
struct dictree *current;
len=strlen(source);
if(len==0)
return
0;
current=root;
for(i=0; i<len;
i++)
{
id=source[i]-‘a‘;
if(current->child[id]!=0)
current=current->child[id];
else
return 0;
}
return
current->n;
}
int main()
{
char
temp[11];
int i;
root=(struct
dictree *)malloc(sizeof(struct dictree));
for(i=0;
i<26; i++)
root->child[i]=0;
root->n=0;
while(gets(temp),strcmp(temp,"")!=0)
insert(temp);
while(gets(temp)!=0)
printf("%d\n",find(temp));
return 0;
}
原文:http://www.cnblogs.com/lxm940130740/p/3565456.html