Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 46267 Accepted Submission(s): 19644
代码:
1 #include<cstdio> 2 3 4 #define rep(i,a,b) for(int i=(a);i<=(b);i++) 5 #define clr(x,y) memset(x,y,sizeof(x)) 6 #define lson l,m,rt<<1 7 #define rson m + 1 ,r,rt<<1 | 1 8 9 const int maxn=50010; 10 11 12 int sum[maxn<<2]; 13 14 void PushUP(int rt) 15 { 16 sum[rt]=sum[rt << 1]+sum[rt << 1|1]; 17 } 18 19 void build(int l,int r,int rt) 20 { 21 int m; 22 23 if(l==r) { 24 scanf("%d",&sum[rt]); 25 return; 26 } 27 28 m=(l+r) >> 1; 29 30 build(lson); 31 build(rson); 32 33 PushUP(rt); 34 } 35 36 void Updata(int x,int add,int l,int r,int rt) 37 { 38 int m; 39 if(l==r) { 40 sum[rt]+=add; 41 return ; 42 } 43 44 m=(l+r) >> 1; 45 if(x<=m) Updata(x,add,lson); 46 else Updata(x,add,rson); 47 48 PushUP(rt); 49 } 50 51 int query(int L,int R,int l,int r,int rt) 52 { 53 int m,ret=0; 54 55 if(L<=l && r<=R) { 56 return sum[rt]; 57 } 58 59 m=(l+r) >> 1; 60 61 if(L<=m) ret+=query(L,R,lson); 62 if(R>m) ret+=query(L,R,rson); 63 64 return ret; 65 } 66 67 int main() 68 { 69 int cas,x,y,n; 70 71 char a[10]; 72 73 scanf("%d",&cas); 74 75 rep(i,1,cas) { 76 printf("Case %d:\n",i); 77 scanf("%d",&n); 78 build(1,n,1); 79 80 while(scanf("%s",a)) { 81 82 if(a[0]==‘E‘) break; 83 scanf("%d%d",&x,&y); 84 85 if(a[0]==‘Q‘) printf("%d\n",query(x,y,1,n,1)); 86 if(a[0]==‘S‘) Updata(x,-y,1,n,1); 87 if(a[0]==‘A‘) Updata(x,y,1,n,1); 88 } 89 } 90 91 return 0; 92 }
原文:http://www.cnblogs.com/sxiszero/p/4076259.html